[백준/BOJ/C++] 10480번 Oddities

[문제]

Some numbers are just, well, odd. For example, the number 3 is odd, because it is not a multiple of two. Numbers that are a multiple of two are not odd, they are even. More precisely, if a number n can be expressed as n = 2 ∗ k for some integer k, then n is even. For example, 6 = 2 ∗ 3 is even.

Some people get confused about whether numbers are odd or even. To see a common example, do an internet search for the query “is zero even or odd?” (Don’t search for this now! You have a problem to solve!)

Write a program to help these confused people.

[입력]

Input begins with an integer 1 ≤ n ≤ 20 on a line by itself, indicating the number of test cases that follow. Each of the following n lines contain a test case consisting of a single integer −10 ≤ x ≤ 10.

[출력]

For each x, print either ‘x is odd’ or ‘x is even’ depending on whether x is odd or even.

[Source Code]

#include <stdio.h>
#include <iostream>
#include <string>
#include <algorithm>
#include <vector>
using namespace std;

int main() {
	int test;
	cin >> test;
	int *arr = new int[test];

	for(int i = 0; i <test; i++){
		int input;
		cin >> input;
		arr[i] = input;
	}

	for(int i = 0; i < test; i++){
		cout << arr[i] <<" is ";
		if(arr[i] % 2 == 0)
			cout << "even\n";
		else
			cout << "odd\n";
	}

}

[결과 화면]